2x(x+1)-2(x^2+4)=

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Solution for 2x(x+1)-2(x^2+4)= equation:


Simplifying
2x(x + 1) + -2(x2 + 4) = 0

Reorder the terms:
2x(1 + x) + -2(x2 + 4) = 0
(1 * 2x + x * 2x) + -2(x2 + 4) = 0
(2x + 2x2) + -2(x2 + 4) = 0

Reorder the terms:
2x + 2x2 + -2(4 + x2) = 0
2x + 2x2 + (4 * -2 + x2 * -2) = 0
2x + 2x2 + (-8 + -2x2) = 0

Reorder the terms:
-8 + 2x + 2x2 + -2x2 = 0

Combine like terms: 2x2 + -2x2 = 0
-8 + 2x + 0 = 0
-8 + 2x = 0

Solving
-8 + 2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 2x = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 2x = 0 + 8
2x = 0 + 8

Combine like terms: 0 + 8 = 8
2x = 8

Divide each side by '2'.
x = 4

Simplifying
x = 4

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